Erreur Compilation Latex

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Erreur Compilation Latex

Messagepar Billy the Kid » Mardi 29 Janvier 2019, 17:18

Bonjour,
Je viens de changer d'ordinateur et viens d'installer la distribution MikTeX 2.9.
J'ai un souci lorsque je compile le code suivant. Il fonctionnait très bien sur mon ancien ordinateur avec MikTeX 2.8.

Code: Tout sélectionner
\documentclass[12pt,a4paper]{article} % article, report ou book. L'option twoside est par défaut incluse avec la classe book
\usepackage[french]{babel} % pour adapter la typographie aux conventions françaises
\usepackage[T1]{fontenc} % pour accéder aux glyphes des fontes
\usepackage[cp1252]{inputenc} % pour compiler correctement sous Windows

\usepackage[paper=a4paper,top=17mm,left=15mm,textheight=26cm,heightrounded,textwidth=17.5cm]{geometry} % réglages format de la page
% paper=a4paper pour éviter les problèmes lors de la création du pdf
% top : marge du haut, left : marge de gauche
% textheight: hauteur du texte, heightrounded : arrondir la hauteur du texte à un nombre entier de lignes, on peut aussi utiliser lines=54 à la place
% textwidth : largeur du texte

\usepackage{amsmath,amssymb,mathrsfs} % pour écrire les maths
\usepackage{fourier} % pour changer de police et utiliser la police utopia

\usepackage{tabularx} % pour la création des tableaux
\usepackage{pstricks-add,pst-eucl} % pour le graphisme
\usepackage{pst-text,pst-tree,pst-eps,pst-fill}
\usepackage{graphicx} % pour inclure des images
\usepackage{xcolor} % pour définir la couleur
\definecolor{0.9white}{rgb}{0.9,0.9,0.9} % définir une couleur

\usepackage{enumitem} % extension pour personnaliser les listes
\setenumerate[1]{noitemsep,topsep=0pt,,font=\bfseries,label=\arabic*)} % 1er niveau : fonte grasse, chiffre arabe suivi d'une parenthèse fermante.
\setenumerate[2]{font=\bfseries,label=\textit{\alph*})} % 2nd niveau : fonte grasse, alphabet-italique suivi d'une parenthèse fermante.
\setenumerate[3]{font=\upshape,label=\textit{\roman*})} % 3ème niveau : fonte normale, chiffre romain minuscule en italique suivi d'une parenthèse fermante.
% noitemsep : pas d'espacement vertical entre les items au sein de la liste
% leftmargin=* : pas de marge gauche pour la liste
% topsep : espacement vertical entre le corps du texte et les items

%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%
% Variante proposée par PG pour éviter la coupure en bas de page avec un enumerate
%
%\makeatletter
%\newif\if@item@no@break@
%\def\item{%
%  \if@item@no@break@
%    \@item@no@break@false
%    \@itempenalty=10000
%    \@beginparpenalty=10000
%  \else
%    \@itempenalty=-\@lowpenalty
%    \@beginparpenalty=-\@lowpenalty
%  \fi
%  \@inmatherr\item
%  \@ifnextchar [\@item{\@noitemargtrue \@item[\@itemlabel]}}
%\newcounter{cptrexo} % définit un nouveau compteur
%\newenvironment*{exof}[1][]
%{%
%\refstepcounter{cptrexo}\setlength{\parindent}{0pt}\psshadowbox[fillcolor=0.9white,framearc=.25]{\textbf{Exercice \thecptrexo\ : #1}}\par\nobreak\smallskip\@item@no@break@true
%}
%{%
%\medskip
%}
%\makeatother
%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%
\makeatletter
\newcounter{cptrexo} % définit un nouveau compteur
\newenvironment*{exof}[1][]
{%
\refstepcounter{cptrexo}\setlength{\parindent}{0pt}\psshadowbox[fillcolor=0.9white,framearc=.25]{\textbf{Exercice \thecptrexo\ : #1}}\par\nobreak\smallskip\@nobreaktrue\everypar{\@nobreakfalse}
}
{%
\medskip
}
\makeatother
% refstepcounter augmente d'une unité la valeur du compteur
% \setlength{\parindent}{0pt} permet de ne pas avoir d'indentation du paragraphe
% \makeatletter\nobreak\@nobreaktrue\everypar{\@nobreakfalse}\makeatother permet de ne pas couper la page entre le titre de l'exercice et l'exercice commençant par un enumerate

\usepackage{fancyhdr,fancybox} % pour définir le style de la page
\fancyhead{}\renewcommand\headrulewidth{0pt} % pour ne pas tracer de trait entre le titre courant et le texte
\pagestyle{fancy}
\fancyhead[C]{\doublebox{\textsc{\LARGE{\thetitre}}}} % le titre centré et doublement encadré
\fancyhead[L]{\textbf{\theclasse}}
\fancyhead[R]{\textit{\thedate}}
\fancyfoot[R]{--~\thepage~--} % numéro de page à droite
\cfoot{\scriptsize\textit{\theauthor, \theclasse{} -- Lycée \textsc{\thelycee}, \theanneescolaire}} % bas de page
\newcommand*{\theanneescolaire}{2018-2019}
\newcommand*{\theclasse}{T\textsuperscript{erm} ES3}
\newcommand*{\thelycee}{La Herdrie}
\newcommand*{\thetitre}{Devoir Surveillé n°5}
\newcommand*{\thedate}{Mercredi 23 Janvier 2019}
\author{Freddy Mérit}

\makeatletter \newcommand*{\theauthor}{\@author}\makeatother % pour redéfinir l'auteur

%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%
%                  Ajouts PERSO
%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%
\newcommand{\ensr}{\ensuremath{\mathbb{R}}} % pour écrire l'ensemble des réels
\newcommand{\ensn}{\ensuremath{\mathbb{N}}} % pour écrire l'ensemble des entiers
\usepackage{tabvar} % pour les tableaux de variations d'une fonction
\newcommand{\calli}[1]{\mathscr #1}
\usepackage[normalem]{ulem} % pour souligner un mot avec une vague
\usepackage{esvect}
%\usepackage[amssymb]{SIunits}
\usepackage{eurosym}
\renewcommand{\leq}{\ensuremath{\leqslant}} % redéfinir le signe inférieur ou égal
\renewcommand{\geq}{\ensuremath{\geqslant}} % redéfinir le signe supérieur ou égal
\usepackage{tkz-tab} % pour la création des tableaux de signes, etc ..
\usepackage[autolanguage]{numprint} % pour insérer des espaces dans l'écriture décimale des nombres
\usepackage{picins}
\usepackage{pst-bar} % pour tracer les diagrammes en bâtons
\usepackage{multicol}
\usepackage{siunitx}
%\usepackage{tangente} % pour tracer les tangentes à la courbe d'une fonction
\DeclareMathOperator{\e}{e} % pour écrire un e droit en mode maths pour l'exponentielle

%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%
%                Interpolation Hermite
%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%

\usepackage{ifthen}
\usepackage{fp}
%% macro trace tangente
\def\traceTangente(#1,#2,#3,#4){%
\ifthenelse{\lengthtest{#4pt>0pt}}{\FPeval\DemiTangenteV{(#3)*(#4)}
\FPeval\TangentXa{(#1)-(#4)}
\FPeval\TangentXb{(#1)+(#4)}
\FPeval\TangentYa{(#2)-(\DemiTangenteV)}
\FPround\TangentYa\TangentYa{3}
\FPeval\TangentYb{(#2)+(\DemiTangenteV)}
\FPround\TangentYb\TangentYb{3}
\psline[linestyle=dashed,linecolor=red,arrowsize=5pt]{<->}(\TangentXa,\TangentYa)(\TangentXb,\TangentYb)}{}}
\makeatletter
%% macro interpolation
\def\Interpolation(#1,#2,#3)(#4,#5,#6){%
\edef\PolyInterp{(x+(-1)*(#4))^2*((1+(-2)*(x+(-1)*(#1))*(#1+(-1)*
(#4))/((#1+(-1)*(#4))^2))*#2+(x+(-1)*(#1))*#3)/((#1+(-1)*(#4))^2)+(x+
(-1)*(#1))^2*((1+(-2)*(x+(-1)*(#4))*(#4+(-1)*(#1))/((#1+(-1)*(#4))^2))
*#5+(x+(-1)*(#4))*#6)/((#1+(-1)*(#4))^2)}%
\psplot[algebraic=true]{#1}{#4}{\PolyInterp}}
%% la   macro principale
\def\HermiteDDL(#1,#2,#3,#4){\def\Hermite@xa{#1}\def\Hermite@ya{#2}\def\Hermite@za{#3}
%\psdot[dotstyle=+,dotscale=1.5,dotangle=45](#1,#2)
\traceTangente(#1,#2,#3,#4)\Hermite@next}

\def\Hermite@next{\@ifnextchar ({\Hermite@job}{\Hermite@end}}

\def\Hermite@job(#1,#2,#3,#4){%
%\psdot[dotstyle=+,dotscale=1.5,dotangle=45](#1,#2)
\Interpolation(\Hermite@xa,\Hermite@ya,\Hermite@za)(#1,#2,#3)
\def\Hermite@xa{#1}\def\Hermite@ya{#2}\def\Hermite@za{#3}
\traceTangente(#1,#2,#3,#4)\Hermite@next}
\def\Hermite@end{}

\makeatother
%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%
\begin{document}
\noindent{\large NOM :\hfill\ PR\'ENOM :\hfill}
\vspace{0,3 cm}

%---------------------------------------------------------------------------------------------------------------------------------------
\begin{exof}[5 points]
Dans un laboratoire, on procède à une culture de bactéries en vue d'une étude biologique.

On admet que le nombre de bactéries $N(t)$ à l'issue de $t$ jours de culture suit une évolution exponentielle et peut ainsi s'exprimer sous la forme $N(t)=C\times q^t$, où $C$ et $q$ sont des nombres réels tels que $C\geq 0$ et $q>0$.

On modélise la situation en concevant que le nombre de bactéries est multiplié par deux tous les cinq jours.

\begin{enumerate}
\item Au début de la culture biologique, le nombre de bactéries présentes est égal à 20.
   \begin{enumerate}
   \item Déterminer le nombre de bactéries à l'issue de 5 jours de culture.
   \item Préciser le nombre de bactéries présentes au bout de 10 jours de culture.
   \item En déduire les valeurs de $N(0)$, $N(5)$ et $N(10)$.
   \end{enumerate}
\item \begin{enumerate}
   \item Exprimer $N(0)$ en fonction de $C$ afin de justifier que $C=20$.
   \item Démontrer que le nombre $q$ vérifie la relation $q^5=2$.
   \item En déduire l'expression du nombre $q$ sous la forme $q=2^a$, où $a$ est un nombre réel que l'on précisera.
   \item Expliquer pourquoi, pour tout nombre réel $t$ positif, on a : $N(t)=20\times 2^{\frac{t}{5}}$.
   \end{enumerate}
\item En utilisant le modèle proposé, déterminer le taux de croissance journalier de la population de bactéries. On l'exprimera sous la forme d'un pourcentage arrondi au centième près.
\item À l'aide de la calculatrice, déterminer le nombre minimal de jours au bout duquel le nombre de bactéries sera supérieur ou égal à $\numprint{2560}$. Justifier la réponse.
\end{enumerate}
\end{exof}

%---------------------------------------------------------------------------------------------------------------------------------------
\begin{exof}[5 points]
\begin{enumerate}
\item En utilisant les puissances de 2, démontrer que $(2^{\frac{5}{2}})^2\times \left(\dfrac{1}{4}\right)^2\times \dfrac{1}{2}=1$.
\item Soit $x$ un nombre réel et soit \rule[-2.5ex]{0pt}{6ex}$A=\dfrac{\sqrt{\e}^{\ 6x+2}}{\e^x}\times\dfrac{5}{\e}$.

Exprimer le nombre $A$ en fonction de $\e^{2x}$.
\item À l'aide des propriétés des fonctions exponentielles, expliquer pourquoi l'on a  : $9^{2,5}+8^{\frac{1}{3}}=245.$
\item Résoudre dans \ensr{} l'équation suivante : $3^{x^2-2x}=27$.
\item Résoudre dans \ensr{} l'équation suivante : $\e^{5x+8}=\left(\dfrac{1}{\e}\right)^2$.

\end{enumerate}
\end{exof}

%---------------------------------------------------------------------------------------------------------------------------------------
\begin{exof}[5 points]
\textit{\begin{small}
D'après Sujets Liban Mai 2016, Amérique du Nord Juin 2017, Antilles-Guyane Juin 2017 et Polynésie 2017.
\end{small}}


\emph{Cet exercice est un questionnaire à  choix multiples (QCM). Pour chacune des cinq questions, quatre réponses sont proposées ; une seule de ces réponses est exacte. Indiquer sur la copie le numéro de la question et la lettre de la réponse choisie sans justifier le choix effectué. Une bonne réponse rapporte un point. Une réponse fausse, une réponse multiple ou l'absence de réponse ne rapporte ni n'enlève aucun point.}

\pagebreak
\begin{enumerate}
\item La représentation graphique d'une fonction $f$ définie et dérivable sur \ensr{} est tracée ci-dessous ainsi que les tangentes aux points $A$ et $B$, d'abscisses respectives $-3$ et $0$.

\begin{center}
\psset{unit=.8cm}
\begin{pspicture}(-7,-3)(5,5)
\def\pshlabel#1{\footnotesize #1}
\def\psvlabel#1{\footnotesize #1}
\def\f{(-58*x^3-957*x^2-5776*x-5481)/1600}
\def\g{5*x^3/27+x^2-1}
\def\h{-3*x^3/250+89*x^2/500-1}
\psgrid[subgriddiv=0,gridlabels=0pt,gridwidth=0.5pt,griddots=10](-7,-3)(5,5)
\psaxes{->}(0,0)(-7,-3)(5,5)[$x$,-90][$y$,180]
\uput[dl](0,-0.1){O}
\psaxes[labelsep=1.8mm,linewidth=1.5pt,ticksize=-2pt 2pt]{->}(0,0)(1,1)
\psplot[algebraic=true,plotpoints=200,linewidth=1.25pt, linecolor=blue]{-7}{-3}{\f}
\psplot[algebraic=true,plotpoints=150,linewidth=1.25pt, linecolor=blue]{-3}{0}{\g}
\psplot[algebraic=true,plotpoints=100,linewidth=1.25pt, linecolor=blue]{0}{5}{\h}
\psline[linewidth=1pt](-5,5)(3,-3)
\psline[linewidth=1pt](-7,-1)(5,-1)
\uput[dr](-6,5){\small{\blue{$\mathcal{C}_f$}}}
\psdots[dotstyle=x,dotscale=1.5](-3,3)(0,-1)(0,0)
\uput[ur](-3,3){$A$}\uput[dr](0,-1){$B$}
\end{pspicture}
\end{center}
 
Alors :
\begin{enumerate}
\begin{tabularx}{\linewidth}{*{4}{X}}
\item $f'(0) = - 1$ & \item  $f'(-1) = 0$ & \item $f'(-3) = - 1$ & \item $f'(-3) = 3$
\end{tabularx}
\end{enumerate}
\item On a tracé ci-dessous la représentation graphique de la dérivée seconde $k''$ d'une fonction $k$ définie sur $[0~;~+ \infty[$.
\begin{center}
\scalebox{0.9}{
\psset{xunit=2cm,yunit=1.2cm}
\begin{pspicture*}(-.5,-1.5)(3.3,3.6)
\def\pshlabel#1{\footnotesize #1}
\def\psvlabel#1{\footnotesize #1}
\def\f{x^2*(x^2-4)/3}
\psgrid[subgriddiv=0,gridlabels=0pt,gridwidth=0.5pt,griddots=15](-1,-2)(4,4)
\psaxes{->}(0,0)(-.5,-1.5)(3.25,3.5)[$x$,-90][$y$,180]
\psaxes[labelsep=.8mm,linewidth=1.5pt,ticksize=-2pt 2pt]{->}(0,0)(1,1)
\uput[dl](0,0){\footnotesize{$0$}}
\psplot[algebraic=true,plotpoints=200,linewidth=1.25pt, linecolor=blue]{0}{3}{\f}
\uput[ur](2,3){\small{\blue{$\mathcal{C}_{k''}$}}}
\end{pspicture*}
}
\end{center}
Alors:
\begin{enumerate}
\begin{tabularx}{\linewidth}{*{2}{X}}
\item $k$ est concave sur l'intervalle [1~;~2].& \item $k$ est convexe sur l'intervalle [0~;~2].\\
\item $k$ est convexe sur $[0~;~+ \infty[$.&\item $k$ est concave sur $[0~;~+ \infty[$.
\end{tabularx}
\end{enumerate}

\item Pour un archer, la probabilité d'atteindre la cible est de $0,8$. Les tirs sont supposés indépendants. La probabilité qu'il touche 3 fois la cible sur une série de 6 tirs est égale à :
\begin{enumerate}
\begin{tabularx}{\linewidth}{*{4}{X}}
\item 0,512 &\item 2,4 &\item \numprint{0,262144} &\item\numprint{0,08192}
\end{tabularx}
\end{enumerate}

\item $A$ et $B$ sont deux évènements d'une expérience aléatoire. On note $\overline{B}$ l'évènement contraire de $B$. On sait que : $P(A) = 0,6$\ , $P(B) = 0,5$ et $P\left(A \cap B\right) = 0,42$. On peut affirmer que :
\begin{enumerate}
\begin{tabularx}{\linewidth}{*{4}{X}}
\item $P_A(B) = 0,3$ & \item $P\left(A \cup B\right) = 0,58$ \\
\item $P_B(A) = 0,84$ & \item $P(A \cap \overline{B}) = 0,28$
\end{tabularx}
\end{enumerate}

\item Une grandeur a augmenté de 5\:\% la première année, puis de 7\:\% la deuxième année.

Sur ces deux années, le pourcentage global d'augmentation est égal à  :

\begin{enumerate}
\begin{tabularx}{\linewidth}{*{4}{X}}
\item 12\:\% & \item  35\:\% & \item 0,35\:\% & \item 12,35\:\% \end{tabularx}
\end{enumerate}
\end{enumerate}
\end{exof}

%---------------------------------------------------------------------------------------------------------------------------------------

\begin{exof}[5 points]
\textit{\begin{small}
Sujet Nouvelle-Calédonie Novembre 2017.
\end{small}}

\emph{\textbf{Dans cet exercice, tous les résultats seront arrondis au millième.}}

\medskip

Une agence de voyage propose des itinéraires touristiques pour lesquels chaque client effectue un aller et un retour en utilisant soit un bateau, soit un train touristique. Le choix du mode de transport peut changer entre l'aller et le retour.

À l'aller, le bateau est choisi dans 65\,\% des cas.

Lorsque le bateau est choisi à  l'aller, il l'est également pour le retour $9$ fois sur $10$.

Lorsque le train a été choisi à  l'aller, le bateau est préféré pour le retour dans 70\,\% des
cas.

\medskip

On interroge au hasard un client. On considère les évènements suivants :

\setlength\parindent{9mm}
\begin{itemize}
\item[$\bullet~~$] $A$ : \og le client choisit de faire l'aller en bateau \fg{} ;
\item[$\bullet~~$] $R$ : \og le client choisit de faire le retour en bateau \fg.
\end{itemize}
\setlength\parindent{0mm}

\medskip
 
On rappelle que si $E$ est un évènement, $p(E)$ désigne la probabilité de l'évènement $E$ et
on note $\overline{E}$ l'évènement contraire de $E$.
 
\medskip
 
\begin{enumerate}
\item Traduire cette situation par un arbre pondéré.
\item On choisit au hasard un client de l'agence.
   \begin{enumerate}
      \item Calculer la probabilité que le client fasse l'aller-retour en bateau.
      \item Montrer que la probabilité que le client utilise les deux moyens de transport est égale à  $0,31$.
   \end{enumerate}
\item On choisit au hasard $20$ clients de cette agence. On note $X$ la variable aléatoire qui
compte le nombre de clients qui utilisent les deux moyens de transport.
   
On admet que le nombre de clients est assez grand pour que l'on puisse considérer que $X$
suit une loi binomiale.
   \begin{enumerate}
      \item Préciser les paramètres de cette loi binomiale.
      \item Déterminer la probabilité qu'exactement $12$ clients utilisent les deux moyens de
transport différents.
      \item Déterminer la probabilité qu'il y ait au moins $2$ clients qui utilisent les deux moyens de transport différents.
   \end{enumerate}
\item Le coût d'un trajet aller ou d'un trajet retour est de \numprint{1560}~\euro{} en bateau ; il est de \numprint{1200}~\euro{}  en train.
   
On note $Y$ la variable aléatoire qui associe, à  un client pris au hasard, le coût en
euro de son trajet aller-retour.
   \begin{enumerate}
      \item Déterminer la loi de probabilité de $Y$.
      \item Calculer l'espérance mathématique de $Y$. Interpréter le résultat.
   \end{enumerate}
\end{enumerate}
\end{exof}

\end{document}


La compilation LaTeX me dit " ] {pgffor.code.tex}
! Paragraph ended before \ProvidesPackageRCS@i was complete.
<to be read again> "



Qui peut me venir en aide pour remédier à ce problème?
J'ai besoin de votre aide.
Merci beaucoup.
Billy the Kid
Hecto-utilisateur
 
Messages: 80
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Localisation: Le Loroux Bottereau (44)
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Re: Erreur Compilation Latex

Messagepar Billy the Kid » Mardi 29 Janvier 2019, 17:22

Voici le fichier log en trois parties:
Code: Tout sélectionner
This is pdfTeX, Version 3.14159265-2.6-1.40.19 (MiKTeX 2.9.6840 64-bit) (preloaded format=latex 2018.12.8)  29 JAN 2019 17:08
entering extended mode
**./Devoir5_TES3.tex
(Devoir5_TES3.tex
LaTeX2e <2018-04-01> patch level 5
("C:\Program Files\MiKTeX 2.9\tex\latex\base\article.cls"
Document Class: article 2014/09/29 v1.4h Standard LaTeX document class
("C:\Program Files\MiKTeX 2.9\tex\latex\base\size12.clo"
File: size12.clo 2014/09/29 v1.4h Standard LaTeX file (size option)
)
\c@part=\count80
\c@section=\count81
\c@subsection=\count82
\c@subsubsection=\count83
\c@paragraph=\count84
\c@subparagraph=\count85
\c@figure=\count86
\c@table=\count87
\abovecaptionskip=\skip41
\belowcaptionskip=\skip42
\bibindent=\dimen102
)
("C:\Program Files\MiKTeX 2.9\tex\generic\babel\babel.sty"
Package: babel 2018/09/26 3.24 The Babel package

("C:\Program Files\MiKTeX 2.9\tex\generic\babel\switch.def"
File: switch.def 2018/09/26 3.24 Babel switching mechanism
)
*************************************
* Local config file bblopts.cfg used
*
("C:\Program Files\MiKTeX 2.9\tex\latex\arabi\bblopts.cfg"
File: bblopts.cfg 2005/09/08 v0.1 add Arabic and Farsi to "declared" options of
 babel
)
("C:\Program Files\MiKTeX 2.9\tex\generic\babel-french\french.ldf"
Language: french 2018/09/14 v3.5c French support from the babel system

("C:\Program Files\MiKTeX 2.9\tex\generic\babel\babel.def"
File: babel.def 2018/09/26 3.24 Babel common definitions
\babel@savecnt=\count88
\U@D=\dimen103

("C:\Program Files\MiKTeX 2.9\tex\generic\babel\txtbabel.def")
\bbl@dirlevel=\count89
)
\l@acadian = a dialect from \language\l@french
\FB@nonchar=\count90
Package babel Info: Making : an active character on input line 414.
Package babel Info: Making ; an active character on input line 415.
Package babel Info: Making ! an active character on input line 416.
Package babel Info: Making ? an active character on input line 417.
\FBguill@level=\count91
\FBold@everypar=\toks14
\FB@Mht=\dimen104
\mc@charclass=\count92
\mc@charfam=\count93
\mc@charslot=\count94
\std@mcc=\count95
\dec@mcc=\count96
\c@FBcaption@count=\count97
\listindentFB=\dimen105
\descindentFB=\dimen106
\labelindentFB=\dimen107
\labelwidthFB=\dimen108
\leftmarginFB=\dimen109
\parindentFFN=\dimen110
\FBfnindent=\dimen111
))
("C:\Program Files\MiKTeX 2.9\tex\latex\carlisle\scalefnt.sty")
("C:\Program Files\MiKTeX 2.9\tex\latex\graphics\keyval.sty"
Package: keyval 2014/10/28 v1.15 key=value parser (DPC)
\KV@toks@=\toks15
)
("C:\Program Files\MiKTeX 2.9\tex\latex\base\fontenc.sty"
Package: fontenc 2017/04/05 v2.0i Standard LaTeX package

("C:\Program Files\MiKTeX 2.9\tex\latex\base\t1enc.def"
File: t1enc.def 2017/04/05 v2.0i Standard LaTeX file
LaTeX Font Info:    Redeclaring font encoding T1 on input line 48.
))
("C:\Program Files\MiKTeX 2.9\tex\latex\base\inputenc.sty"
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Package: amssymb 2013/01/14 v3.01 AMS font symbols

Dernière édition par Billy the Kid le Mardi 29 Janvier 2019, 17:25, édité 1 fois.
Billy the Kid
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Re: Erreur Compilation Latex

Messagepar Billy the Kid » Mardi 29 Janvier 2019, 17:24

Voici la deuxième partie :
Code: Tout sélectionner
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Package: amsfonts 2013/01/14 v3.01 Basic AMSFonts support
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LaTeX Font Info:    Overwriting math alphabet `\mathfrak' in version `bold'
(Font)                  U/euf/m/n --> U/euf/b/n on input line 106.
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File: t1enc.def 2017/04/05 v2.0i Standard LaTeX file
LaTeX Font Info:    Redeclaring font encoding T1 on input line 48.
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Package textcomp Info: Sub-encoding information:
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(textcomp)               4 = 5 + \texteuro
(textcomp)               3 = 4 + \textohm
(textcomp)               2 = 3 + \textestimated + \textcurrency
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File: ts1enc.def 2001/06/05 v3.0e (jk/car/fm) Standard LaTeX file
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("C:\Program Files\MiKTeX 2.9\tex\generic\pgf\utilities\pgfutil-common-lists.te
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Billy the Kid
Hecto-utilisateur
 
Messages: 80
Inscription: Lundi 02 Novembre 2009, 18:04
Localisation: Le Loroux Bottereau (44)
Statut actuel: Actif et salarié | Enseignant

Re: Erreur Compilation Latex

Messagepar Billy the Kid » Mardi 29 Janvier 2019, 17:26

Et la troisième partie :
Code: Tout sélectionner

("C:\Program Files\MiKTeX 2.9\tex\generic\pgf\utilities\pgfkeysfiltered.code.te
x"
\pgfkeys@tmptoks=\toks31
)) ("C:\Program Files\MiKTeX 2.9\tex\generic\pgf\utilities\pgffor.code.tex"
Runaway argument?
] {pgffor.code.tex}
! Paragraph ended before \ProvidesPackageRCS@i was complete.
<to be read again>
                   \par
l.11
     
I suspect you've forgotten a `}', causing me to apply this
control sequence to too much text. How can we recover?
My plan is to forget the whole thing and hope for the best.

("C:\Program Files\MiKTeX 2.9\tex\generic\pgf\math\pgfmath.code.tex"
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Package: defpattern 1994/10/12
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Package: fp-pas 1994/08/29
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Package: fp-random 1995/02/23
\FPseed=\count432
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("C:\Program Files\MiKTeX 2.9\tex\latex\fp\fp-eqn.sty"
Package: fp-eqn 1995/04/03
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Package: fp-upn 1996/10/21
)
("C:\Program Files\MiKTeX 2.9\tex\latex\fp\fp-eval.sty"
Package: fp-eval 1995/04/03
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\openout1 = `Devoir5_TES3.aux'.

LaTeX Font Info:    Checking defaults for OML/cmm/m/it on input line 149.
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("C:\Program Files\MiKTeX 2.9\tex\latex\base\ts1cmr.fd"
File: ts1cmr.fd 2014/09/29 v2.5h Standard LaTeX font definitions
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LaTeX Font Info:    ... okay on input line 149.
LaTeX Font Info:    Try loading font information for T1+futs on input line 149.


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File: t1futs.fd 2004/03/02 Fontinst v1.926 font definitions for T1/futs.
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LaTeX Info: Redefining \degres on input line 149.
LaTeX Info: Redefining \dots on input line 149.
Package french.ldf Info: Setting StandardItemizeEnv=true for
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LaTeX Info: Redefining \up on input line 149.

*geometry* driver: auto-detecting
*geometry* detected driver: dvips
*geometry* verbose mode - [ preamble ] result:
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* \mag=1000
* \@twocolumnfalse
* \@twosidefalse
* \@mparswitchfalse
* \@reversemarginfalse
* (1in=72.27pt=25.4mm, 1cm=28.453pt)


("C:\Program Files\MiKTeX 2.9\tex\latex\translator\translator-basic-dictionary-
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Dictionary: translator-basic-dictionary, Language: English
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File: siunitx-abbreviations.cfg 2017/11/26 v2.7k siunitx: Abbreviated units
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\symtvsymbols=\mathgroup10


Package tabvar Warning: Le type de colonne N est d\'efini par ailleurs.
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9.

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File: ts1futs.fd 2004/03/26 Fontinst v1.926 font definitions for TS1/futs.
)

LaTeX Font Warning: Font shape `TS1/futs/m/sc' undefined
(Font)              using `TS1/futs/m/n' instead
(Font)              for symbol `textdegree' on input line 203.


Package Fancyhdr Warning: \headheight is too small (12.0pt):
 Make it at least 24.08229pt.
 We now make it that large for the rest of the document.
 This may cause the page layout to be inconsistent, however.

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[1

]
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LaTeX Font Info:    Font shape `U/futm/m/n' will be
(Font)              scaled to size 10.07397pt on input line 223.
LaTeX Font Info:    Font shape `U/futm/m/n' will be
(Font)              scaled to size 7.63599pt on input line 223.
LaTeX Font Info:    Font shape `FMX/futm/m/n' will be
(Font)              scaled to size 9.19998pt on input line 250.
LaTeX Font Info:    Font shape `FMX/futm/m/n' will be
(Font)              scaled to size 6.99199pt on input line 250.
LaTeX Font Info:    Font shape `U/futm/m/n' will be
(Font)              scaled to size 9.19998pt on input line 250.
LaTeX Font Info:    Font shape `U/futm/m/n' will be
(Font)              scaled to size 6.99199pt on input line 250.
 [2] [3] (Devoir5_TES3.aux)

LaTeX Font Warning: Some font shapes were not available, defaults substituted.

 )
Here is how much of TeX's memory you used:
 34116 strings out of 492971
 655155 string characters out of 3135881
 857641 words of memory out of 3000000
 37352 multiletter control sequences out of 15000+200000
 669039 words of font info for 158 fonts, out of 3000000 for 9000
 1141 hyphenation exceptions out of 8191
 61i,17n,69p,700b,622s stack positions out of 5000i,500n,10000p,200000b,50000s

Output written on Devoir5_TES3.dvi (3 pages, 88364 bytes).
Billy the Kid
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Re: Erreur Compilation Latex

Messagepar balf » Mardi 29 Janvier 2019, 20:34

Bonsoir,

Il est difficile de répondre quoi que ce soit : votre code compile sans erreur (juste deux malheureux warnings), et le .log que vous postez en trois parties ne comporte pas le message que vous mentionnez.

Juste quelques remarques au passage : un des warnings est émis par fancyhdr et vous recommande de faire passer headheight à 24pt, ce qui est simple à faire à partir de geometry. D'autre part, le nom du lycée devrait être en petites capitales italiques, le reste étant en italiques. Cela peut se faire en chargeant erewhon, un clone d'utopia qui fournit les compléments nécessaires à fourier.
Dernière remarque : de nos jours, il est recommandé d'utiliser utf8 pour l'encodage d'entrée — ce qui est le défaut pour la plupart des éditeurs modernes, et ce que suppose xelatex.

B. A.
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Re: Erreur Compilation Latex

Messagepar jcs » Mardi 29 Janvier 2019, 20:36

Bonjour

votre texte compile bien chez moi
j'ai juste enlevé picins et changé cp 1252 en utf8

Latex + dvi
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Re: Erreur Compilation Latex

Messagepar marco56 » Mercredi 30 Janvier 2019, 13:04

Pas de souci non plus, il va falloir tenter d'isoler le problème (le package fautif ?).
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